Moderators: Lady of Mystery, nickj, Mandrake, bananafish, support, Rob
Kroots wrote:Surely the answer to the boy girl ratio riddle is:
3 Boys and 4 Girls
The one boy has 2 brothers becaus ehe is one of the 3 boysgiving him 4 sisters which is double the amount of brothers he has and the girl has just as many sisters as brothers - 3 sisters and 3 brothers.
Bigtone53 wrote:The key point is that as the moon orbits the earth once in 28 days, the same side of the moon always faces us. For this to happen, the moon must spin on its axis once in the same 28 days, so the length of its 'day' (sunrise to sunrise) is 28 earth days.
Kroots wrote:Surely if the boy is an only child his has no other sisters and no other brothers giving him the same amount of (nonexistant) brothers as sisters.
Lawrence wrote:ooo, shall I start proving that 2=1 and that everyone in the country is in fact a woman? there are a few "proofs" of these things around.
MagicBell wrote:Lawrence wrote:ooo, shall I start proving that 2=1 and that everyone in the country is in fact a woman? there are a few "proofs" of these things around.
You sound like someone with a maths background, at least in part. Are you?
Maths can also 'prove' that women are evil, and while that one is a little flawed, it is at least, really quite funny.
Lawrence wrote:I do indeed have a maths degree.
I havn't seen the "women are evil one" does it run along the same lines as the "money is the route of all evil" 'proof'?
MagicBell wrote:Lawrence wrote:I do indeed have a maths degree.
I havn't seen the "women are evil one" does it run along the same lines as the "money is the route of all evil" 'proof'?
Ah nice, that makes two of us.
Its based on money being the route of all evil, as well as a couple of other well known facts/phrases.
http://www.anvari.org/fun/Gender/Women_are_Evil.html
That's basically it. It could perhaps be displayed better, but that was the first link i found.
MagicBell wrote:The proof that there are more values between, say, 1 and 2, than there are integers (whole numbers).
Users browsing this forum: Google [Bot] and 2 guests