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Charles Calthrop wrote:Actually no! Thinking about it I am right!
The first choice has a one in five chance of being right. The second a one in four etc. So it's 5*4*3*2*1 (obviously the final card must be correct if the other four are. This gives a probability of 120:1.
3125 is 5 to the power of 5. This would be a valid if the choice was 5 cards from five full sets of symbols, but it isn't. This means you can discount a lot of combinations like 5 circles, for instance. Since there is only one of each symbol available this cuts the odds dramatically. I stand by 120:1.
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