talkmagic.co.uk

well 11/13*100=84.6% as this is worked out by a computer it probobly rounds this down
2/13*100=15.38 this is deffintly rounded down so
who nicked 1%
the computer

QED

(sorry iv'e just finished a very VERY hard maths examand needed some thing simple to cool my brain down

Pcwizme

Since we are onto odd maths, how about this?

start with a=b.

Then a-b+b=b

Divide both sides by (a-b):

(a-b+b)/(a-b)=b/(a-b)
or:

1+b/(a-b)=b/(a-b)

so if we subtract b/(a-b) from both sides we get:

1=0

lol, quite diverting that, shame it's completely wrong!

Where did 1+b/(a-b) come from? If a and b are equal a-b+b equals b, not b+1.

Was the idea to covetly slip the one in by blinding everyone with figures and divisions by zero? If so, I apologise for spoiling it for everyone.

Gosh, I feel like a right nerd now.

While I'm in killjoy mood, how about the popular e-mail currency that is "Mathmatical proof that girls are evil"? For those that have avoided it somehow, it goes like this;

First we state that girls require time and money:
Girls = Time * Money
And we all know that Time is Money:
Time = Money
Therefore:
Girls = Money * Money = Money²
And because "Money is the root of all evil":
Money = √Evil
Therefore:
Girls = (√Evil)²
We are forced to conclude that:
Girls = Evil

The flaw in this is at the outset;

First we state that girls require time and money:
Girls = Time * Money

This expresses time and money as seperate rather than connected commodities and suggests the correct formula should be the sum and not the product of time and money, or to put it another way:

Girls = Time + Money

So to follow it through from this point,

girls = money + money = 2money

culminating in

girls = 2 x (√Evil)

Which says that girls are actually a little bit evil, the precise quantity varying according to the amount of money involved.

Also, this method fails to even consider the additional variables of nagging accumen, friends who don't like you, need to feel more assertive, need for pressies and feeling of gender superiority (aka Greer's constant).

Call me the Masked Mathmagician at your peril.

(a-b+b)/(a-b)=(a-b)/(a-b)+b/(a-b)=1+b/(a-b)

And yes, it works 'cos a-b=0 so you are dividing by 0 which doesn't give a number, so all of the calculation from that point on is meaningless.

Ok, how about this one:

Three men in a cafe. The bill comes to £25 but the men each only have a ten pound note so they hand over £30 to the waiter who comes back with 5 £1 coins as change. Since they can't split this three ways they each take £1 and give the remaining £2 to the waiter, so each of them pays £9.

However, 3x9=27 and 27+2 =29 so what happened to the extra pound?

HHHmmmmm

yes they all paid £9
yes 3x9 = £27

but the bill was £25, so £27 - £25 = £2 which went to the waiter...

nice try

lol, I'll find one you can't crack, oh yes I will hahahahahahahahahaha

Perhaps the margin of error in the phpBB board poll system is 1%? I don't know.... email the people who made the message board script hahaha

Really, the reason is simple... ontill ALL the talkmagic users have voted the two percentages will not add up to 100%... i think.

Quicksand Kerry Devile wrote:Which says that girls are actually a little bit evil, the precise quantity varying according to the amount of money involved.

Indeed - I have met women that will be VERY NASTY to you, in a private setting, for around £300 per night...

Sorry, couldn't resist...

Wow that maths hurt - but then again us recruitment consultants aren't known for our brains

Sadly throwing in a post that is on topic I'm right handed but overhand shuffle and deal with my left (almost unable to do it with my right). I can charlier cut with both but my left hand is more likely to drop the little buggers all over the floor.

I do find therefore that I have to reverse a lot of the stuff in the Royal Road etc

I find this all very strange...

perhaps 1% are ambidextrous.

Ambidextrous and people with no hands!

Three men in a cafe.
The confusion arises because £29 is close to £30, but there is no reason why what the three men pay and the waiter's tip should add up to the money they came in with. For example: again they come in with £10 each (£30 in total), the bill comes to £5 (the cafe is not in London), from the £25 change they take back £8 each and leave the remaining £1 for the waiter. They each came in with £10 and left with £8, so they each spent £2.
£2 x 3 (their total spend) + £1 for the waiter = £7: nothing like the £30 they started with and no reason why they should be similar except coincidentally.
If they had taken back £1 each and left a very generous £22 (£25-£3) for the waiter then the amount they spent £27 (£9x3) + the waiter's tip of £22 would add up to £49. Again nothing like the original £30 (and again, no reason why they should be similar).

On the maths: You are all banging your head against a wall. This is an old math trick. You are mixing two different forms of math and the two will not come out in the wash, hence the tipping problem and not working out properly. It's like using a calculator, based on tens, to figure out inches, which is a system based on twelves. They just don't mix. So, there is no answer to your problem.

On the left handed thing: The fact of the matter is, you should be learning your sleights with both hands. Ambidexterity can be learned and the hands should be trained equally. Jugglers will tell you that!

Mike.