bananafish wrote:I beg to differ. I think you will find that 101010 is binary for 42. I assume you are counting from the other end. Not sure why you would do that.
'Tis true.
I used to program in binary many moons back (think 1983!) and unfortunately in my capacity as a known anorak, I can speak it fluently - although in those days it was all 8-bit - which could only ever give a number as high as 256 and as low as zero - but it's easily adaptable!
I couldn't cope with todays 64-bit processing without pen and paper...
BUT... I can VOUCH that 101010 is 42, as a 6-bit binary figure. As 8-bit, it would appear with two leading zeros... 00101010. I think where Nick is getting mixed, as Bananafish states, is that he's counting from the right - which is correct in a sense, as 00000001 would be 1, whereas 10000000 would be 128.
Sorted?
As the book (HHGTTG) states, what is the question?
